1650D - Twist the Permutation - CodeForces Solution

brute force constructive algorithms implementation math *1300

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Python Code: 

from collections import deque

def solve():
    n = int(input())
    ans = [0] * (n + 1)
    deq = deque([int(i) for i in input().split()])
    for i in range(n, 0, -1):
        while deq[len(deq) - 1] != i:
            deq.append(deq.popleft())
            ans[i] += 1
        deq.pop()
    for i in range(1, len(ans)):
        print(ans[i], end = ' ')
    print()
            

for i in range(int(input())):
    solve()

C++ Code: 

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

#define forn(i, n) for (int i = 0; i < int(n); i++)


void solve() {
    int n;
    cin >> n;
    int a[n];
    for (int i = 0; i < n; ++i) {
        cin >> a[i];
    }
    int ans[n];
    for (int i = n; i > 0; --i) {
        int ind = 0;
        for (int j = 0; j < i; ++j) {
            ind = a[j] == i ? j : ind;
        }
        int b[i];
        for (int j = 0; j < i; ++j) {
            b[(i - 1 - ind + j) % i] = a[j];
        }
        for (int j = 0; j < i; ++j) {
            a[j] = b[j];
        }
        ans[i - 1] = i != 1 ? (ind + 1) % i : 0;
    }
    for (int i = 0; i < n; ++i) {
        cout << ans[i] << ' ';
    }
    cout << '\n';
}
int main() {
    int tests;
    cin >> tests;
    forn(tt, tests) {
        solve();
    }
}


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